Regex in Java - Regular Expression

Question

I have a problem in Regular expression. I need to print and count the words starts with word ‘ge’ and end with either word ‘ne’ or ‘me’. When I running the code only words start with "ge" appear. Can anyone help me to improve my source code?

Pattern p = Pattern.compile("ge\\s*(\\w+)");
Matcher m = p.matcher(input);

int count=0;
List<String> outputs = new ArrayList<String>();

while (m.find()) {
    count++;
    outputs.add(m.group());
    System.out.println(m.group());
}

System.out.println("The count is " + count);

vks · Accepted Answer · 2015-10-08 04:26:40Z

1

\bge\w*[nm]e\b

This should do it for you.

In java this would be

\\bge\\w*[nm]e\\b

use \b to denote word boundary

answered Oct 8, 2015 at 4:26

vks

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Comments

d0nut · Accepted Answer · 2015-10-08 04:27:01Z

0

Well you're kinda missing the second half of your regex

ge\s*(\w+)[nm]e

This will work.

Regex101

answered Oct 8, 2015 at 4:27

d0nut

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