How to fix error in int to Binary String

Question

I am trying to convert an integer to a binary number string, and I wrote the code for it and it compiled. However, I can't seem to write a test file for it, i keep getting an error. I am supposed to write a separate test file that outputs my answer, however I am not sure how to do that. I'm pretty new to Java. Can anyone help me figure out how to fix the error I get?

This is my java code for to convert it.

public String binaryNumber( int j)       
{

    String n = "";
    String a = "";


    do
    {
        a += (j % 2);
        j = j/2;         

    }while (j != 0);

    for(int r = (a.length() - 1); r >=0; r--)
     {
        n += a.charAt(r);
     }

    return n;
}

 public String getN {return n;}

This is my test code :

public class BinaryNumberTest
{
  public static void main(String[] args)
   {
    System.out.println("Result: " + binaryNumber(45));
   }

 }

Your binaryNumber must be static

Suresh Atta
– Suresh Atta

2015-10-09 20:42:22 +00:00
Commented Oct 9, 2015 at 20:42 — Suresh Atta
– Suresh Atta, Commented Oct 9, 2015 at 20:42

Channa Jayamuni · Accepted Answer · 2015-10-09 20:50:44Z

1

Your code seems correct if you make the binaryNumber(int j) method static. Because you can't access non-static method inside static context.

However you can use Integer.toBinaryString(x) to perform the task easily. Additionally, you can use Integer.toString(x,8) to convert octal, Integer.toString(x,2) to convert binary, Integer.toString(x,16) to convert hexa-decimal, and Integer.toString(x,n) to n base.

edited Oct 9, 2015 at 20:50

answered Oct 9, 2015 at 20:44

Channa Jayamuni

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2 Comments

showp1984 Over a year ago

I assume this is a homework question, where the purpose of the task is to do it manually. So using Integer.toBinaryString(x) would defeat the purpose. :)

Grey Over a year ago

Thank you, changing it to static did work. I edited my test code and now I get an error again. I need to put an integer and then call out to it in my test code. Is there a way to do that?

jh314 · Accepted Answer · 2015-10-09 20:45:43Z

0

You should make your binaryNumber method static because you are not using instance fields.

public class BinaryNumber 
{
    public static String binaryNumber( int j)       
    {

        String n = "";
        String a = "";


        do
        {
            a += (j % 2);
            j = j/2;         

        }while (j != 0);

        for(int r = (a.length() - 1); r >=0; r--)
         {
            n += a.charAt(r);
         }

        return n;
    }
}

To test:

public class BinaryNumberTest
{
  public static void main(String[] args)
   {
    System.out.println("Result: " + BinaryNumber.binaryNumber(45));
   }

 }

answered Oct 9, 2015 at 20:45

jh314

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1 Comment

Grey Over a year ago

Thank you for helping. I edited my original post with changes to the test code. Could you help me with that?

Mureinik · Accepted Answer · 2015-10-09 20:44:05Z

0

First, since binaryNumber doesn't use any instance members it could (read: should) be defined as static. Second, you need to reference it by its class name, or statically import it:

System.out.println("Result: " + BinaryNumber.binaryNumber(45));

answered Oct 9, 2015 at 20:44

Mureinik

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