How to match URL with regex number?

Question

I'm trying to match a URL which it can be generated with any random numbers, for example, these urls:

www.domain.com/products/id?=292
www.domain.com/products/id?=132
www.domain.com/products/id?=698

There a code to compare URL with random number is equal, this currently code won't work.

var url1= "www.domain.com/products/id?=292";
var url2= "www.domain.com/products/id?=7542";
var url3= "www.domain.com/products/id?=5401";


var numberPat = /[0-9]/;    

    if(url3 ==  "www.domain.com/products/id?=" + numberPat){ 
        alert("Domain with random number is MATCHED")
    }
    else{
        alert("Domain with random number is NOT matched")
    }

I made a jsfiddle, http://jsfiddle.net/n5s2pvkr/1/ Im looking a solution that could return as true with matched url with random number

EDIT: I cannot accept url3.match(numberPat) for some reason, I need to do exactly like:

www.domain.com/products/id?=+numberPat due to selective comparison.

I would extract the value (by getting text after =) then do a isNaN to see if they are numbers. No need for regex. — Script47
– Script47, Commented Oct 9, 2015 at 21:12

arcyqwerty · Accepted Answer · 2015-10-09 21:24:26Z

You want to use repetition in your regex /\d+/ to match more than one digit.

Also, why are you trying to add a regex to a String?

If you want to check the URL, you're probably looking for

url1.match(/^www\.domain\.com\/products\/id\?=\d+$/)

^ Start at the beginning
www\.domain\.com\/products\/id\?= find this exact string
\d+ find any number of digits
$ must be end of string

http://jsfiddle.net/n5s2pvkr/3/

var url1= "www.domain.com/products/id?=292";
var url2= "www.domain.com/products/id?=7542";
var url3= "www.domain.com/products/id?=5401";

function isMatch(url) {
    if(url.match(/^www\.domain\.com\/products\/id\?=\d+$/)){ 
        return "Domain with random number is MATCHED";
    }
    else{
        return "Domain with random number is NOT matched";
    }
}

alert([url1, url2, url3].map(function(url) {
    return isMatch(url);
}).join('\n'));

Edit:

Reading your question again, I think you were shooting matching the digits of the URL then comparing it like

if (url3 == "www.domain.com/products/id?=" + url3.match(/\d+/))`

which is a little redundant since you could just match on the static part of the string as well.

Code with fewest modifications: http://jsfiddle.net/n5s2pvkr/4/

var url1= "www.domain.com/products/id?=292";
var url2= "www.domain.com/products/id?=7542";
var url3= "www.domain.com/products/id?=5401";


var numberPat = /[0-9]+/;    

if(url3 ==  "www.domain.com/products/id?=" + url3.match(numberPat)){ 
    alert("Domain with random number is MATCHED")
}
else{
    alert("Domain with random number is NOT matched")
}

It actually worked what I excepted, thank you for reading my reason!

Script47 · Accepted Answer · 2015-10-09 21:15:54Z

2

As I suggested in my comment you can do this without regex:

var url2= "www.domain.com/products/id?=7542";
var url3= "www.domain.com/products/id?=5401";

if (isNaN(url2.split("=")[1]) == false) {
    alert("Is number.");   
} else {
    alert("NAN");   
}

Note: this will break if you have multiple keys.

Example

http://jsfiddle.net/dxyt8Ldm/

answered Oct 9, 2015 at 21:15

Script47

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1 Comment

Ivan Over a year ago

It didn't help me because it only needs to match ...products/id?=234, not ...profile/id?=234, ...store/id?=234, ...promotion/id?=234

anubhava · Accepted Answer · 2015-10-09 21:19:00Z

2

To build your regex dynamically use new RegExp(...) like this:

var url1= "www.domain.com/products/id?=292";
var url2= "www.domain.com/products/id?=7542";
var url3= "www.domain.com/products/id?=5401";
numberPat = '[0-9]+';

// build your regex here
var re = new RegExp("www\\.domain\\.com/products/id\\?=" + numberPat)

// now test it
re.test(url3)
true
re.test(url2)
true
re.test(url1)
true

answered Oct 9, 2015 at 21:19

anubhava

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1 Comment

anubhava Over a year ago

Not sure how you tried. If you copy/paste above code in JsFiddle it will work fine.

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