here's the code:
reg = /(\d{3}\.){3}\d{3}/;
var str8 = "111.222.333.444";
console.log(str8.match(reg));
the result:Array [ "111.222.333.444", "333." ] test in firefox
the first result I can expect but what I can't expect is the second result. can anyone tell me why it get second result and tell me how to fix to get only the first one.
thanks~!
Capturing groups appear in String#match (without /g modifier) results as parts of the resulting array.
If the regular expression does not include the g flag, returns the same result as RegExp.exec().
And exec() help says:
If the match succeeds, the
exec()method returns an array and updates properties of the regular expression object. The returned array has the matched text as the first item, and then one item for each capturing parenthesis that matched containing the text that was captured.
To get rid of them, just replace capturing groups with non-capturing ones:
reg = /(?:\d{3}\.){3}\d{3}/;
// ^^
var str8 = "111.222.333.444";
console.log(str8.match(reg));Result: ["111.222.333.444", index: 0, input: "111.222.333.444"].
?:,/(?:\d{3}\.){3}\d{3}/;(?:\d{3}\.){3}\d{3}.