Try this...
var fileNames = ["87-1.json", "7-4.json", "102-4.json"]
// Modded OP's order to actually test sort
var sorted = fileNames.sort{ $0 < $1 }
print(sorted) // ["102-4.json", "7-4.json", "87-1.json"]
// Not sorted as OP "required", as they are string sorted, not number sorted
// Very simplistic solution
sorted = fileNames.sort { ($0 as NSString).integerValue < ($1 as NSString).integerValue}
print(sorted) // As OP requires, but...
// It won't sort on his count field - add a failing case...
fileNames = ["7-4.json", "87-1.json", "102-4.json", "102-1.json"]
sorted = fileNames.sort { ($0 as NSString).integerValue < ($1 as NSString).integerValue}
print(sorted) // ["7-4.json", "87-1.json", "102-4.json", "102-1.son"]
// WRONG!
// Define a simple function that parses his strings into tuples.
// This assumes that the Strings are valid, and fails safe if not.
// If you want more validation, add it yourself!
func myParse(s: String) -> (Int, Int) {
let c = s.componentsSeparatedByCharactersInSet(NSCharacterSet(charactersInString: "-."))
switch c.count {
case 0:
print("Careful Will Robinson!")
return (0, 0)
case 1:
print("Careful Will Robinson!")
return ((c[0] as NSString).integerValue, 0)
default:
return ((c[0] as NSString).integerValue, (c[1] as NSString).integerValue)
}
}
let test = fileNames.map { myParse($0) }
print("\(test)") // Test execution of function
sorted = fileNames.sort { (s1: String, s2: String) -> Bool in
let t1 = myParse(s1)
let t2 = myParse(s2)
if t1.0 == t2.0 {
return t1.1 < t2.1
} else {
return t1.0 < t2.0
}
}
print(sorted) // As required ["7-4.json", "87-1.json", "102-1.json", "102-4.json"]
let array2 = array.sort { $0.compare($1, options: .NumericSearch) == .OrderedAscending }did the job for me