Swift: sorting of array is not done correctly

Question

I am using this to sort components in an array in Swift:

myArray = myArray.sorted { $0.localizedCaseInsensitiveCompare($1) == NSComparisonResult.OrderedAscending }

However, it gives me the following result:

[18C, 18L, 18R, 22, 24, 27, 36C, 36L, 36R, 4, 6, 9]

Is it possible to sort it the right way, i.e.

[4, 6, 9, 18C, 18L, 18R, 22, 24, 27, 36C, 36L, 36R]

Rob · Accepted Answer · 2015-10-12 16:33:33Z

8

You can use compare with .NumericSearch:

array.sortInPlace { $0.compare($1, options: .NumericSearch) == .OrderedAscending }

or

let array2 = array.sort { $0.compare($1, options: .NumericSearch) == .OrderedAscending }

answered Nov 16, 2014 at 5:27

Rob

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5 Comments

In Swift 2 sorted() has been replaced by sort().

This does not work if the entry begins with a String instead of a number.

@MountainMan: That is not true. Try it with the array ["file1.txt", "file10.txt", "file2.txt"].

Can you write an extension for using it esier?

Yes, you can, if you want.