PHP multidimensional array - Counting the duplicate and mingle the duplicate with original

Question

$users = array(
              array(1,'name1'),
              array(1,'name1'),
              array(2,'name2'),
              array(3,'name3')
         );

Now after adding the following code, i can make the unique array.

array_map("unserialize", array_unique(array_map("serialize", $users)));

I can count the duplicates with the following code. But it is missing the name field. So, i need to do something to get the name along with the id and count of duplicate.

array_count_values(array_map(function($item) {
        return $item['id'];
    }, $users));

Do i need to loop the array get something like this? Or is there any other trick in php?

$new_users = array(
              array(1,'name1', 2), //two times + descending order 
              array(2,'name2', 1), 
              array(3,'name3', 1)
         );

Upvote for using the word "mingle". It feels like an 80' school dance. — Andrei
– Andrei, Commented Oct 13, 2015 at 9:03
Not exactly same, but a similar question here - stackoverflow.com/questions/14202108/… — pankaj
– pankaj, Commented Oct 13, 2015 at 9:09
Instead of showing a bunch of almost correct code, describe what you're actually trying to achieve. You want to merge all duplicates into one item and count the number of duplicates? — deceze
– deceze ♦, Commented Oct 13, 2015 at 9:11
@deceze I am updating the final result which i am expecting. It is all working good. Is there anyway to achieve them in shortest code to reduce the work load. — Mahesh
– Mahesh, Commented Oct 13, 2015 at 9:15

deceze · Accepted Answer · 2015-10-13 09:15:58Z

2

$new_users = array_reduce($users, function (array $new_users, array $user) {
    $key = sha1(serialize($user));
    if (isset($new_users[$key])) {
        $new_users[$key][2]++;
    } else {
        $new_users[$key] = array_merge($user, [1]);
    }
    return $new_users;
}, []);

To deduplicate, use unique keys in an array. Here we use the hash of the serialised array as key, which is the simplest way to uniquely identify something more complex than a single value. Then simply increase a counter if the item already exists.

answered Oct 13, 2015 at 9:15

deceze♦

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