Combine php strings with substr and strpos into one string

Question

Not sure if this has been asked but what's the best way to combine three strings into one string. I tried adding an array but it didn't work.

My strings are: $linktitle = get_the_title(); $linkt = substr($linktitle, 0, strpos($linktitle, ' —')); $linkt2 = substr($linktitle, 0, strpos($linktitle, ' –')); $linkt3 = substr($linktitle, 0, strpos($linktitle, ' |'));

Example $linktitle outputs:

Facebook Creates YouTube-Like Video Feature Inside Facebook | Re/code WNYC to Open New Podcast Division – The New York Times

My attempt at combination didn't work: $linkall = substr($linktitle, 0, strpos($linktitle, array(' —', –',' |')));

What I would like to accomplish is combine —, –, and | into an array like in the above example (if possible).

You're not making sense. Combine how? Explain more clearly what you want to achieve. — Sami Kuhmonen
– Sami Kuhmonen, Commented Oct 13, 2015 at 22:54
Please also include an example of what the content of $linktitle is. — Twisty
– Twisty, Commented Oct 13, 2015 at 22:56
@PedroLobito Clearly not since in the example the array is inside strops and has nothing to do with the three outputs. I can guess the attempt, but the question should be clear — Sami Kuhmonen
– Sami Kuhmonen, Commented Oct 13, 2015 at 23:05

Stas · Accepted Answer · 2015-10-13 22:55:00Z

1

How about using implode() on the array containing your strings?

Something like

$pieces = array($string1, $string2, $string3);
$result = implode('', $pieces);

In your case perhaps this makes more sense:

$pieces=array();
$pieces[] = substr($linktitle, 0, strpos($linktitle, ' —'));
$pieces[] = substr($linktitle, 0, strpos($linktitle, ' &#8211;'));
$pieces[] = substr($linktitle, 0, strpos($linktitle, ' |'));
$result = implode('', $pieces);
echo $result;

answered Oct 13, 2015 at 22:55

Stas

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1 Comment

Gregory Schultz Over a year ago

Thanks! Solved problem.

Sergio Ivanuzzo · Accepted Answer · 2015-10-13 22:57:33Z

0

Looks like, you have missed one quote before –

strpos($linktitle, array(' |', '&#8211;',' |')));

answered Oct 13, 2015 at 22:57

Sergio Ivanuzzo

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