Inline JavaScript code not working

Question

I want to change image while mouseover and mouseout

MY Code :

<img src="convert.php?file=image.gif" title="Preview image"
   width="100" height="100" rel="image.gif"
   onmouseover="this.src=this.rel"
   onmouseout="this.src='convert.php?file='+this.rel" />

this.rel getting undefined. Please check and help me. :(

What are you expecting this.rel to be? I don't see any reason for it to have a value. — Paul Kienitz
– Paul Kienitz, Commented Oct 14, 2015 at 10:37

h0mayun · Accepted Answer · 2015-10-14 10:36:05Z

2

<img src="convert.php?file=image.gif" title="Preview image"
   width="100" height="100" rel="image.gif"
   onmouseover="this.src=this.getAttribute('rel')"
   onmouseout="this.src='convert.php?file='+this.getAttribute('rel')" />

answered Oct 14, 2015 at 10:36

h0mayun

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1 Comment

h0mayun Over a year ago

ur welcome.you can accept the answer if my answer helped you.

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