PyQt no button.clicked.connect function?

Question

I've got PyQt4 with a python 3.4 and there is this strange bug occurring. Whenever I try to call btn.clicked.connect(), Pycharm will throw this error:

Cannot find reference "connect" in "function".

So for example:

btn = QtGui.QPushButton("Quit", self)
btn.clicked.connect(QtCore.QCoreApplication.instance().quit)

will throw this error. How? Do I have missing files?

try: self.button = QtGui.QPushButton('Quit', self) and self.btn.clicked.connect(QtCore.QCoreApplication.instance().quit) — Radagast
– Radagast, Commented Oct 14, 2015 at 17:19
A workaround might be self.connect(btn, SIGNAL("clicked()"), the_slot) if self derives from QWidget — stellasia
– stellasia, Commented Oct 14, 2015 at 17:29

ivan_pozdeev · Accepted Answer · 2015-10-14 17:31:19Z

3

According to Events and Signals in PyQt4 - PyQt4 Tutorial - ZetCode:

PyQt4.5 introduced a new style API for working with signals and slots.
QtCore.QObject.connect(button, QtCore.SIGNAL('clicked()'),self.onClicked)
This is the old style API.
button.clicked.connect(self.onClicked)
The new style adheres more to the Python standards.

answered Oct 14, 2015 at 17:31

ivan_pozdeev

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1 Comment

nerdoc Over a year ago

Eh, what "works" here? Python does execute this correctly, yes. But Pycharm and it's Python analysis does still not correctly handle button.clicked.connect(self.onClicked). The warning persists, because it can not defer the type of clicked. Any hints here how to make this work?

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