PHP: How can I print multi-dimensional array elements using foreach?

Question

$shop = array( 
                array("Rose", 1.25 , 15),
                array("Daisy", 0.75 , 25),
                array("Orchid", 1.15 , 7)
            );


    for($i = 0; $i <= count($shop); $i++){
        foreach($shop[$i] as $key => $val)
            echo $key . ' = ' . $val . '<br>';
    }

So this is the output I'm getting:

0 = Rose

1 = 1.25

2 = 15

0 = Daisy

1 = 0.75

2 = 25

0 = Orchid

1 = 1.15

2 = 7

============================================

But then I get an error:

Warning: Invalid argument supplied for foreach()

What I want to know is how to correct this, and if there's a more efficient way to write what I'm trying to output?

Thanks guys.

Philipp · Accepted Answer · 2015-10-16 01:25:08Z

2

The problem is, your using <= instead of <. So your for loop goes one step to far and the array is out of bounds.

for($i = 0; $i < count($shop); $i++){
    foreach($shop[$i] as $key => $val)
        echo $key . ' = ' . $val . '<br>';
}

answered Oct 16, 2015 at 1:25

Philipp

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3 Comments

user557846 Over a year ago

or 2 foreach rather than the for

mincedMinx Over a year ago

I feel dumb. Thanks budd!

Philipp Over a year ago

No need to - sometimes one doesn't see the obvious

Malitta N · Accepted Answer · 2015-10-16 01:32:52Z

1

When iterating through an array, always use a foreach instead of a for loop.

foreach ($shop as $foo) {
    foreach ($foo as $key => $val) {
        echo $key . ' = ' . $val . '<br />';
    }   
}

answered Oct 16, 2015 at 1:32

Malitta N

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Comments

Daryl Gill · Accepted Answer · 2015-10-16 01:29:13Z

0

foreach ($Array AS $Values){
    if (is_array($Values)){
        foreach ($Values AS $Inner){
            echo $Inner;
        }
    }else{
        echo $Values;
    }
}

I Personally would go for 2 foreach loops. Check if the value passed is an array, if it is. Step in. If not, print the value

answered Oct 16, 2015 at 1:29

Daryl Gill

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