I have two arrays:
let arr1 = ["one.json", "two.json", "three.json"]
let arr2 = ["one.json", "three.json"]
Now I want to remove all values of arr2 in arr1, so my expected result in the example above would be let arrFiltered = ["two.json"]. I know how to handle this using a for-loop, however, I thought there may is an easier and more performance-oriented solution?
You have to use Set instead of Array in this case.
let arr1 = Set(["one.json", "two.json", "three.json"])
let arr2 = Set(["one.json", "three.json"])
arr1.subtract(arr2)
Fundamental Set Operations
The illustration below depicts two sets–a and b– with the results of various set operations represented by the shaded regions.
Solution using the filter function
let arr1 = ["one.json", "two.json", "three.json"]
let arr2 = ["one.json", "three.json"]
let arrFiltered = arr1.filter{ !arr2.contains($0) }
