PHP Date format question

Question

Some folks helped me on How to check the data format in PHP post but I need to check two date formats MM-DD-YYYY and DD-MM-YY instead of one. Do I need to setup two regular expression???? Thanks for the help!!!

$date1=05/25/2010;    
$date2=25/05/10;    //I wish both of them would pass 

$date_regex = '!^(0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])[- /.](19|20)\d\d$!';

if (preg_match($date_regex, $date1)) {
  do something    
}

if (preg_match($date_regex, $date2)) {  // need second Reg. expression??
  do something    
}

Erm, you should put your dates into quotes. Otherwise 05/25/2010 is just an arithmetic expression (05 divided by 25 divided by 2010). — Gumbo
– Gumbo, Commented Jul 24, 2010 at 19:37
I know. In my application, I use mktime. my code is only for demo. purpose... — user401184
– user401184, Commented Jul 24, 2010 at 19:38

BoltClock · Accepted Answer · 2010-07-24 20:39:28Z

3

Your regex

$date_regex = '!^(0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])[- /.](19|20)\d\d$!';

matches MM-DD-YYYY format.

The other you want to match is simple

$date_regex2 = '!^(0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])[- /.]\d\d$!';

You could just check if either is true.

if(preg_match($date_regex,$date) or preg_match($date_regex2,$date)){
  //match
}

Or you could combine them using

$mmddyyyy = '!^(0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])[- /.](19|20)\d\d$!';
$mmddyy = '!^(0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])[- /.]\d\d$!';
$regex = "($mmddyyyy|$mmddyy)";

if(preg_match($regex,$date){
  //match
}

Not the most elegant regex but it shold work just fine.

edited Jul 24, 2010 at 20:39

BoltClock

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answered Jul 24, 2010 at 19:52

Chris

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