How to loop through the number at each index in byte array?

Question

I'm coding a program to parse xml to a byte array, and need to check the numeric values at certain indexes within the byte array.

For example if 99 is an integer within the array, it should write an error message to the console, same for 999 and 01.

What I've tried so far is the using a for each loop, but the if..else conditions are checking the index number, not the integer numbers associated with each index in the array.

Does anyone know how I can loop through the integer values associated with each index? (shown in the screen shot below)

This is what I've tried so far, but the loop seems to be checking the index values , not the integer values associated with the indexes, giving false results:

private static byte[] requestBytes;

foreach(char i in requestBytes)
{
    if (i == 99)
    {
        Console.WriteLine("Sending Failure..");
    }
    else if(i == 999)
    {
        Console.WriteLine("Message Failure..");
    }
    else if (i == 01)
    {
        Console.WriteLine("Sending Success..");
    }

}

As you can see in the picture, each index has an associated integer value, which I want to check in a loop.

How can 999 possibly be a value in an element of the byte array? — Klitos Kyriacou
– Klitos Kyriacou, Commented Oct 28, 2015 at 0:12

Ayoub M. · Accepted Answer · 2015-10-28 09:40:33Z

2

You could try a for loop

for(int i = 0; i < requestBytes.Length; i++)
                {
                    var v = requestBytes[i];
                    if (v == 99)
                    {
                        Console.WriteLine("Sending Failure..");
                    }
                    else if(v == 999)
                    {
                        Console.WriteLine("Message Failure..");
                    }
                    else if (v == 01)
                    {
                        Console.WriteLine("Sending Success..");
                    }

                }

edited Oct 28, 2015 at 9:40

answered Oct 28, 2015 at 1:22

Ayoub M.

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2 Comments

Brian Var Over a year ago

okay will try that solution instead, there is a small typo above..should be for, not foreach.

Ayoub M. Over a year ago

Yes, sorry my mistake, I was sleepy.

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