Print Variable/Dynamic List of String

Question

I have a list of string with variable length. I do know that the minimum length of the list is 4. How do I print the list in the following format if the list grows to more than 4?

>>> strlist = ['a', 'b', 'c', 'd', 'f', 'g'] # Unknown length
>>> print ('%s %s %s %s' % (strlist [2], strlist [0], strlist [4], strlist [5]))

c a f g

If the list expands to

[..., 'h', 'i', 'j']

then I want the output to be

c a f g h i j

Obviously, I can't put 500 "%s" in my print function if the list expands so I'm hoping there's a better way.

You are printing the list elements in random order, is it intentional? — Ahasanul Haque
– Ahasanul Haque, Commented Nov 3, 2015 at 19:21
print('%s %s %s' % (strlist[2], strlist[0], ' '.join(strlist[4:])))? — Two-Bit Alchemist
– Two-Bit Alchemist, Commented Nov 3, 2015 at 19:22
In Python % is an operator for constructing strings -- not really anything to do with print per se. If for a given application % isn't adequate for getting the string that you want -- construct the string some other way and then print it. — John Coleman
– John Coleman, Commented Nov 3, 2015 at 19:27

NPE · Accepted Answer · 2015-11-03 19:27:21Z

4

I would first transform the list as required and then use str.join():

>>> print (" ".join([strlist[2]] + [strlist[0]] + strlist[4:]))
c a f g h i j

Depending on your exact requirements (which are not entirely clear from your question) the transformation code might need to be different. However, the overall "transform then join" pattern still applies.

edited Nov 3, 2015 at 19:27

answered Nov 3, 2015 at 19:23

NPE

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1 Comment

Two-Bit Alchemist Over a year ago

Upvote assuming we understood this weird pattern correctly

Zizouz212 · Accepted Answer · 2015-11-04 00:42:35Z

-1

If formatting isn't an issue, then this should work:

print (" ".join(strlist))

edited Nov 4, 2015 at 0:42

Zizouz212

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answered Nov 3, 2015 at 19:27

Illusionist

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