problem with passing variables with php

Question

I'm trying to pass variables using "get" in php, but ran into a snag.

Here's my PHP file:

<?php
 include '../includes/header.php';
?>
 <div id="page">
  <div id="content">
   <h3><?php $_GET['head']; ?></h3>
   <div id="screenshots"> <img src="../images/sites/<?php $_GET['img1']; ?>" /> <img src="../images/sites/<?php $_GET['img2']; ?>" /> </div>
   <div id="description">
    <p><?php $_GET['p1']; ?></p>
    <p><?php $_GET['p2']; ?></p>
   </div>
  </div>
 </div>
 <?php
 include '../includes/footer.php';
?>

To test it out I made a simple request:

<a href="work/test.php?head=a&img1=b&img2=c&p1=d&p2=e"><img src="images/sites/thumbs/thumb.jpg"/></a>

It goes to the correct page but none of the variables are getting seen. Did I make a stupid mistake somewhere? Thanks!

Sarfraz · Accepted Answer · 2010-07-28 19:17:22Z

6

You need to echo them all, here is an example:

  <p><?php echo $_GET['p1']; ?></p>
  <p><?php echo $_GET['p2']; ?></p>

answered Jul 28, 2010 at 19:17

Sarfraz

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1 Comment

Marco Ceppi Over a year ago

If php.ini is setup for it (I think short_tags?) You can <?= $_GET['p1']; ?> the = is interrupted as "echo" saving the 6 extra characters. But it's not usually recommended.

Mchl · Accepted Answer · 2010-07-28 19:17:59Z

0

You're not echoing your variables <?php $_GET['img1']; ?> should be <?php echo $_GET['img1']; ?>

answered Jul 28, 2010 at 19:17

Mchl

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Comments

Jimmy · Accepted Answer · 2010-07-28 19:18:19Z

0

Your variables aren't getting written, you need an echo statement.

Try something like this:

<p><?php echo $_GET['p1']; ?></p>

answered Jul 28, 2010 at 19:18

Jimmy

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