I have two commands which both return numbers. For example:
cat `find -name \*.cd -print` | wc -l
cat `find -name \*.c -print` | wc -l
Let's say that the first one returns 10, the other 5.
What would the command which return the sum of them, without changing these commands, look like?
I need something like this:
cat `find -name \*.cd -print` | wc -l + cat `find -name \*.c -print` | wc -l
and it should return 15 in this case.
How I can do that?
That command will execute yours two commands and print the sum of the results.
echo $(($(cat `find -name \*.cd -print` | wc -l) + $(cat `find -name \*.c -print` | wc -l)))
EDIT: As @Karoly Horvath commented it would be more readable if it's not a oneliner:
cd_count=$(cat `find -name \*.cd -print` | wc -l)
c_count=$(cat `find -name \*.c -print` | wc -l)
echo $(($cd_count + $c_count))
$ expr $(echo 5) + $(echo 10)
15
Just replace the echo statements with your commands.
It's better to combine the two searches:
cat $(find -regex '.*\.cd?$') | wc -l
or
find -regex '.*\.cd?$' | xargs cat | wc -l
or, if you filenames can contain spaces:
find -regex '.*\.cd?$' -print0 | xargs -0 cat | wc -l
$ in regex. in case the file name had more periods(.)...