Node.js soap request remove namespace from argument

Question

I am unable to send the correct argument to the service.

Code used:

var soap = require('soap');
var url = 'http://example.com';

soap.WSDL.prototype.ignoredNamespaces = ['targetNamespace', 'typedNamespace'];

var args = {'name':'test'};

soap.createClient(url, function(err, client) {
    client.Hello(args, function(err,result,res){
        console.log(result);
        console.log(client.lastRequest);
    });
});

The Hello-function should return string "Hello test !". However, I get:

'Hello null !'

The request being sent is:

<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" ....><soap:Body>
<tns:Hello xmlns:tns="http://example/">
    <tns:name>test</tns:name>
</tns:Hello></soap:Body></soap:Envelope>

where test is the interesting part. The service is expecting

<name>test</name>

without namespace (i tested this with http://www.soapclient.com/)

So, the question is: how do I send the request argument without tns attached? (tns:name => name) Thanks!

Oscar Rico · Accepted Answer · 2016-05-25 15:45:43Z

3

The correct way to override namespace is to send the parameters like this:

var params = { ':name' : 'test' }

It's in documentation: Overriding the namespace prefix

answered May 25, 2016 at 15:45

Oscar Rico

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Comments

AStopher · Accepted Answer · 2016-05-17 08:11:33Z

0

In your code instead of passing argument as

var args = {'name':'test'};

try

var args = {arg0: 'testName'};

I am not an expert but it worked for me to pass an argument from node.js while invoking SOAP client.

edited May 17, 2016 at 8:11

AStopher

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answered May 17, 2016 at 7:52

user3350549

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