In most interpreted languages (example given in psuedo PHP) I would be able to do something like this
function f($name, &$errors = null) {
if(something_wrong) {
if(!is_null($errors) {
$errors[] = 'some error';
}
return false;
}
}
if(!f('test', $errs = array()) {
print_r($errs);
}
And get a result like
Array
(
[0] => some error
)
However when I try this in Python
def f(name, errors = None):
if something_wrong:
if errors:
errors.append('some error')
return False
if not f('test', errs = []):
print str(errs)
I get an error
TypeError: f() got an unexpected keyword argument 'errs'
Which makes perfect sense in the context of Python thinking I am trying to set a specific argument, and not create a new variable altogether.
However if I try
if not f('test', (errs = [])):
print str(errs)
I get
f('test', (errs = []))
^
SyntaxError: invalid syntax
Because I think now it assumes I am trying to create a tuple.
Is there any way to keep this code on one line, or do I absolutely have to initialise the variable on it's own before passing it to the function/method? From what I can tell the only solution is this
errs = []
if not f('test', errs):
print str(errs)