I'm trying to write a program that will have a user input size for an array, and then take values into that array. I initially tried
int sz = 51;
double Arr[sz];
Which led to compilation errors. Apparently dynamic allocation of the variable has to happen, and I'd rather avoid that if possible. So I modified my code (current state as shown below) which now only throws "expected primary-expression before ']' token". Is there a way to fix this and I'm just not seeing it, or do I need to use dynamic allocation?
Thanks for your time!
#include <iostream>
#include <iomanip> //for setprecision
using namespace std;
int sz = 51;
double n=0;
double Arr[0];
void get_input(double Arr[], int &sz){ //gets input
do{
cout<< "Enter size: "<< endl;
cin>> sz;
if (sz<0 || sz>50){
cout<< "Invalid size, enter a value between 0 and 50"<<endl;
}
}while(sz<0 || sz>50);
for( int i=0; i<sz; i++){
cin>> Arr[i];
}
}
double calcSum( double Arr[], int sz){ //finds sum
for(int i=0; i<sz; i++){
n+= Arr[i];
}
return(n);
}
void printArray(double Arr[], int sz){ //prints array elements
for(int i=0; i<sz; i++){
cout<< Arr[i]<< setprecision(2)<<" ";
if(i%7 == 0)
cout<< endl;
}
}
int main()
{
double Arr[sz];
get_input(Arr[], sz); //error here
printArray(Arr[], sz); //error here
return 0;
}
get_input(Arr[])makes no sense.Arris already an array, you don't need to keep putting[]there, unless you want to use the subscript operator. Also,szis still not a constant expression. Make itconst int sz = 51;and that will work. Minus the parts where you try to modifysz.