Is it possible to add a matrix to a structure 'column' without using a for-loop? For example I have a structure with 3 fields
A.name
A.grade
A.attendance
now A.attendance expects a 1x5 matrix. If I have a 5x5 matrix, can I directly insert it into 5 rows of the structure A? something like
A(1:5).attendance = B
where B is a 5x5 matrix
If your B is actually a 5 element cell array where each element is a 1-by-5 matrix (actually each element can contain anything), then
[A.attendance] = B{:}
will work. You can convert your 5-by-5 double matrix B to the desired form as follows:
B_cell = mat2cell(B, ones(size(B,1),1),size(B,2))
or skip the temp variable and use deal:
[A.attendance] = deal(mat2cell(B, ones(size(B,1),1),size(B,1)))
deal directly on the cell without {:}. These things always confuse me!
{:} is itself an implicit deal. Using explicitly deal allows you to use a full cell, deal will deal with it for you.deal allows you to use a "manually" defined comma-separated list on the RHS: [A(1:5).attendance] = deal(1,3,5,7,9);. That doesn't work without deal. But if that 1,3,5,7,9 list is automatically generated from a cell array C = {1,3,5,7,9} as C{:}, then deal is not necessary from Matlab 7.0 onwards, even though C{:} produces precisely 1,3,5,7,9
You can convert B to a cell array of its rows,
C = mat2cell(B, ones(size(B,1),1), size(B,2))
and then you can assign as follows
[A(1:size(B,2)).attendance] = C{:};
deal:)A, [A.attendance] should work toodeal on the right-hand side. It used to be necessary, but it's not anymore since version 7.0A is previously undefined or sufficiently small. If A has more than size(B,1) entries it will give an error