Get two dimensions of a three dimensional array C#

Question

In java I could do it like this:

Square[][][] sheets;
public final Square[][] getSheet(int index) {
    return sheets[index];
}

What is the equivalent in c#? Since the syntax for multidimensional arrays is a little different:

Square[,,] Sheets;
public Square[,] GetSheet(int index) {
    return ????
}

Technically, that isn't a multidimensional array in java, that's an array of arrays. You can do the same in C#. — Robert McKee
– Robert McKee, Commented Nov 10, 2015 at 18:11
It does not make sense to take 2 dimensions of 3d array(not talking about jagged array, they are 1d). You have to specify which dimensions? XY? XZ? YZ? — M.kazem Akhgary
– M.kazem Akhgary, Commented Nov 10, 2015 at 18:19
sheet index and x,y, so I suppose the best way to go about it would be: [][,] — Vincas Stonys
– Vincas Stonys, Commented Nov 10, 2015 at 18:21
@VincasStonys I agree - if you are really modelling an array of 2-D arrays then Square[][,] may be the cleanest structure. — D Stanley
– D Stanley, Commented Nov 10, 2015 at 18:32

D Stanley · Accepted Answer · 2015-11-10 18:47:32Z

6

The equivalent in C# is the same if you are using jagged arrays:

private Square[][][] sheets;
public Square[][] GetSheet(int index) 
{
    return sheets[index];
}

If you have a multi-dimensional array there's not a simple way to get two of the three dimensions. The best you can do is recreate an array:

private Square[,,] sheets;
public Square[,] GetSheet(int index) 
{
    int x = sheets.GetLength(0);      
    int y = sheets.GetLength(1); 

    Square[,] sheet = new Square[x,y];
    for(int i = 0; i < x; i++)
    for(int j = 0; j < y; j++)
         sheet[i,j] = sheets[i,z,index];

    return sheet;
}

How do I initialize a Square[4][4][4]?

You can either loop and initialize each dimension:

for(int i = 0; i < 4; i++)
{
    sheets[i] = new Square[4][];
    for(int j = 0; j < 4; j++)
    {
        sheets[i][j] = new Square[4];
    }
}

(Note that if Square is a reference type, then you also need to initialize each Square[i][j][k] to a value, otherwise it will be null)

or use array initialization syntax;

sheets = new Square[4][][]
{
     new Square[4][] {new Square[4], new Square[4], new Square[4], new Square[4],},
     new Square[4][] {new Square[4], new Square[4], new Square[4], new Square[4],},
     new Square[4][] {new Square[4], new Square[4], new Square[4], new Square[4],},
     new Square[4][] {new Square[4], new Square[4], new Square[4], new Square[4],},
};

Obviously, looping scales much more easily that initialization syntax.

edited Nov 10, 2015 at 18:47

answered Nov 10, 2015 at 18:13

D Stanley

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3 Comments

Sergey Kalinichenko Over a year ago

...or Square[][,] sheets if OP does not need to further project his squares.

Vincas Stonys Over a year ago

I'm not tied to multi-dimensional arrays, so using jagged are fine. What is the correct way then to rewrite this from java to c#: Sheets = new Square[4][4][4]; ? Is it: Sheets = new Square[4][][]; ?

D Stanley Over a year ago

@VincasStonys That's the first step. you then need to loop and initialize each dimension (sheets[i] = new int[4][]; sheets[i][j] = new int[4];)

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