New pandas DataFrame from another DataFrame based on a unique multiple column index

Question

I'm trying to create a new pandas.DataFrame from another pandas.DataFrame based on a unique multiple column index. I'm able to create a pandas.core.index.MultiIndex using df.index.drop_duplicates() with the correct results, but I can't figure out how to convert it to a pandas.DataFrame.

The following script creates the original DataFrame using a SQL Query.

import sqlite3 as db
import pandas as pd

conn = db.connect('C:/data.db')
query = """SELECT TimeStamp, UnderlyingSymbol, Expiry, Strike, CP, BisectIV, OTMperc FROM ActiveOptions
           WHERE TimeStamp = '2015-11-09 16:00:00' AND UnderlyingSymbol = 'INTC' AND
           Expiry < '2015-11-27 16:00:00' AND OTMperc < .02  AND OTMperc > -.02
           ORDER BY UnderlyingSymbol, Expiry, ABS(OTMperc)"""

df = pd.read_sql_query(sql=query, con=conn,index_col=['TimeStamp', 'UnderlyingSymbol', 'Expiry'],
                       parse_dates=['TimeStamp', 'Expiry'])

The script creates the following DataFrame:

In[6]: df
Out[6]: 
                                                          Strike  CP  BisectIV  OTMperc
TimeStamp           UnderlyingSymbol Expiry                                            
2015-11-09 16:00:00 INTC             2015-11-13 16:00:00    33.5  -1    0.2302  -0.0045
                                     2015-11-13 16:00:00    33.5   1    0.2257   0.0045
                                     2015-11-13 16:00:00    33.0  -1    0.2442   0.0105
                                     2015-11-13 16:00:00    33.0   1    0.2426  -0.0106
                                     2015-11-13 16:00:00    34.0   1    0.2240   0.0191
                                     2015-11-13 16:00:00    34.0  -1    0.2295  -0.0195

                                     2015-11-20 16:00:00    33.5   1    0.2817   0.0045
                                     2015-11-20 16:00:00    33.5  -1    0.2840  -0.0045
                                     2015-11-20 16:00:00    33.0  -1    0.2935   0.0105
                                     2015-11-20 16:00:00    33.0   1    0.2914  -0.0106
                                     2015-11-20 16:00:00    34.0   1    0.2718   0.0191
                                     2015-11-20 16:00:00    34.0  -1    0.2784  -0.0195

Creating a new DataFrame with a unique multiple column index generates the following output:

In[10]: new_df = df.index.drop_duplicates()
In[11]: new_df
Out[11]: 
MultiIndex(levels=[[2015-11-09 16:00:00], [u'INTC'], [2015-11-13 16:00:00, 2015-11-20 16:00:00]],
           labels=[[0, 0], [0, 0], [0, 1]],
           names=[u'TimeStamp', u'UnderlyingSymbol', u'Expiry'])

In[12]: type(new_df)
Out[12]: pandas.core.index.MultiIndex

Any ideas?

agold · Accepted Answer · 2015-11-11 08:29:10Z

The problem is that you set new_df to the index list with the duplicates removed:

new_df = df.index.drop_duplicates()

What you want is to select only the rows which do not have duplicate indices. You can use the duplicated function to filter your old data frame:

new_df = df[~df.index.duplicated()]

A small example, based on this:

#create data sample with multi index
arrays = [['bar', 'bar', 'baz', 'baz', 'foo', 'foo', 'qux', 'qux'],
          ['one', 'one', 'one', 'two', 'one', 'two', 'one', 'one']]
#(the first and last are duplicates)
tuples = list(zip(*arrays))
index = pd.MultiIndex.from_tuples(tuples, names=['first', 'second'])
s = pd.Series(np.random.randn(8), index=index)

The original data:

>>> s
first  second
bar    one      -0.932521
       one       1.969771
baz    one       1.574908
       two       0.125159
foo    one      -0.075174
       two       0.777039
qux    one      -0.992862
       one      -1.099260
dtype: float64

And filtered for duplicates:

>>> s[~s.index.duplicated()]
first  second
bar    one      -0.932521
baz    one       1.574908
       two       0.125159
foo    one      -0.075174
       two       0.777039
qux    one      -0.992862
dtype: float64

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