Unable to get Json array value in PHP

Question

Guys i have tried to get the JSON array value through PHP. its not returning any value

{
"transactionTime": "2015-11-14T03:36:11-08:00",
"receipt": "********",

"lineItems": [
    {
        "itemNo": "1",

    }
],

}

in PHP i have tried this code

Here $decrypted contains the above formatted JSON value.

$order = json_decode($decrypted);
$id = $order['transactionTime'];

Could anyone look at it . thanks guys

Rajdeep Paul · Accepted Answer · 2015-11-14 11:53:00Z

1

Try this:

$order = json_decode($decrypted, true);
$id = $order['transactionTime'];

Edited

When you set assoc parameter in json_decode() function to TRUE, the returned objects will be converted into associative arrays.

answered Nov 14, 2015 at 11:53

Rajdeep Paul

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6 Comments

Rockstar Over a year ago

I have removed the comma $id = $order['lineItems']['itemNo']; is that correct to get itemNo value ?? because its not getting the value..

Rajdeep Paul Over a year ago

yes, that's correct. That should give you the itemNo. By the way, as @n-dru pointed out, your json is incorrect, please remove the trailing comma after "itemNo": "1" and after final ]. You can validate your json here

Rajdeep Paul Over a year ago

You json is valid, and oh! I was wrong, since lineItems is an array, this is what you would do to get itemNo, $id = $order['lineItems'][0]['itemNo'];.

Rajdeep Paul Over a year ago

Happy to hear. Please upvote and accept the answer. :)

Rockstar Over a year ago

Hey buddy $cbemail = $order['customer']['billing']['email']; doesnot return any value ??

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n-dru · Accepted Answer · 2015-11-14 11:56:31Z

0

Your json string is invalid - remove trailing comma after "itemNo": "1" and after final ].

answered Nov 14, 2015 at 11:56

n-dru

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1 Comment

Rockstar Over a year ago

Here the complete string textuploader.com/56wwg

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