Passing arguments in function dynamically in Python 3

Question

Does python support dynamic argument passing when I call a function?

  import itertools.product
  l = [1,2,3,95,5]
  for i in range(5):
      for n in itertools.product(l,l):
         #calculations that
         #reduce set size

I want through the iterations of i the product to be:

i=1: product(l,l)

i=2: product(l,l,l)

i=3: product(l,l,l,l)

...

If I can recall correctly the only language I know that supports that kind of functionality is PHP.

falsetru · Accepted Answer · 2015-11-15 01:27:54Z

3

itertools.product accepts an optional keyword argument repeat:

So, you can do:

for n in itertools.product(l, repeat=i+1):
    ...

Alternatively, to dynamically pass argument, you can use *args (See Unpacking argument lists):

for n in itertools.product(*([l] * (i+1))):
    ...

answered Nov 15, 2015 at 1:27

falsetru

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