How to replace a string inside of Json using java

Question

[
    "label": {
        "originalName"      : "Case #",
        "modifiedLabel"     : "Case #",
        "labelId"           : "case_number_lbl",
        "isEditable"        : "true",
        "imageClass"        : ""
    }
]

In the above Json Array I need to replace "Case #" with "Ticket #". This is occuring in somany places. Any one update please. Thanks In advance.

This is not a valid json. If you have an array [ ... ] the elements inside do not have names. "label": should not be there. — Jaroslaw Pawlak
– Jaroslaw Pawlak, Commented Nov 17, 2015 at 12:29

Jaroslaw Pawlak · Accepted Answer · 2015-11-17 12:33:32Z

I think a simple loop should solve your problem:

public static void main(String[] args) throws JSONException {
    JSONArray array = new JSONArray("[" +
            "    {" +
            "        originalName      : \"Case #\"," +
            "        modifiedLabel     : \"Case #\"," +
            "        labelId           : \"case_number_lbl\"," +
            "        isEditable        : \"true\"," +
            "        imageClass        : \"\"" +
            "    }" +
            "]");

    System.out.println(array.toString(2));

    for (int i = 0; i < array.length(); i++) {
        JSONObject object = array.getJSONObject(i);
        JSONArray keys = object.names();
        for (int j = 0; j < keys.length(); j++) {
            String key = keys.getString(j);
            if (object.getString(key).equals("Case #")) {
                object.put(key, "Ticket #");
            }
        }
    }

    System.out.println();
    System.out.println(array.toString(2));
}

Joker · Accepted Answer · 2015-11-17 10:19:07Z

2

You can use GSON to convert your json to java Object and then you can change your string .

answered Nov 17, 2015 at 10:19

Joker

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Comments

Reg · Accepted Answer · 2015-11-17 10:47:46Z

1

You can exchange the value with the help String.replaceAll()

String jSONString = ...; // Your JSon string
String newString = jSONString.replace("Case #", "Ticket #");

edited Nov 17, 2015 at 10:47

answered Nov 17, 2015 at 10:23

Reg

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2 Comments

Tom Over a year ago

Can you explain why you prefer to use replaceAll over replace?

Reg Over a year ago

Hi Tom, replace is a better match, (I agree). replaceAll uses regex, where replace only uses a CharSequence

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