How to read a resource file to a byte array in scala?

Question

I just want to read file in resource and get a byte array? Can someone help me with that?

Almost a duplicate of stackoverflow.com/questions/27360977/… (that one tries to read lines instead of bytes, but maybe you can adapt it, for example by combining it with stackoverflow.com/questions/7598135/…) — Thilo
– Thilo, Commented Nov 17, 2015 at 11:19

poki2 · Accepted Answer · 2020-09-01 07:43:28Z

3

Note: this requires Java 9+

I use the following to read a file in my resources as byte array:

getClass.getResourceAsStream("/file-in-resource-folder").readAllBytes()

edited Sep 1, 2020 at 7:43

answered Aug 31, 2020 at 14:23

poki2

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Community · Accepted Answer · 2017-05-23 12:15:55Z

2

As described in How to read a file as a byte array in Scala, the following fragment should do the trick:

def slurp(resource: String) = {
  val bis = new BufferedInputStream(getClass.getResource(resource))
  try Stream.continually(bis.read).takeWhile(-1 !=).map(_.toByte).toArray
  finally bis.close()
}

edited May 23, 2017 at 12:15

CommunityBot

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answered Nov 17, 2015 at 12:01

Norwæ

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1 Comment

m.bemowski Over a year ago

This approach is very slow and heavy on CPU, because it reads the file byte by byte, one byte at a time.

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