java.lang.NumberFormatException from parsing a string to a double

Question

I cant figure it out

double d = Double.valueOf(str);
double d2 = Double.parseDouble(str);

both methods produce the following exception:

java.lang.NumberFormatException: Invalid double: "‎-73.04"

However, the following hardcoded value works just fine:

double d = Double.valueOf("-73.04");

So the problem is in the content of the string. The dot and/or minus characters are maybe not the same as in your hardcoded example. — assylias
– assylias, Commented Nov 17, 2015 at 23:07
Have you tried to trim your string passed to both methods? It might contains additional characters like whitespace or line return that these methods don't understand. — orion78fr
– orion78fr, Commented Nov 17, 2015 at 23:08
im reading data from xls file, some of data is good, but some crashing from some reason — itzhar
– itzhar, Commented Nov 17, 2015 at 23:12
does your string itself contains double quotes or does it contain leading or trailing spaces ? — Juned Ahsan
– Juned Ahsan, Commented Nov 17, 2015 at 23:12

rgettman · Accepted Answer · 2015-11-17 23:13:41Z

2

After copying the number from the title of this question and pasting into IntelliJ between double-quotes, it became clear what the problem is:

double d = Double.parseDouble("\u200E-73.04");

Exception in thread "main" java.lang.NumberFormatException: For input string: "?-73.04"

Copying it from your hard-coded -73.04 does not have this behavior.

You have a "left-to-right mark" Unicode character in your string somehow. You must eliminate that extraneous Unicode character from your string before parsing it.

answered Nov 17, 2015 at 23:13

rgettman

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