I want to delete this from a string:
[QUOTE=*] * [/QUOTE]
.* kan be anything
Can anyone please provide a pattern that I can use?
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I need to use the text after that quoted stuffJay– Jay2010-07-31 10:34:15 +00:00Commented Jul 31, 2010 at 10:34
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which part do you need to use? the first * or the second one?Jhong– Jhong2010-07-31 10:40:31 +00:00Commented Jul 31, 2010 at 10:40
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I hope you know that BBCode is not a regular language and thus cannot be parsed with regular expression.Gumbo– Gumbo2010-07-31 10:45:40 +00:00Commented Jul 31, 2010 at 10:45
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I need the part after [/QUOTE] and that seems to work unless there's a <br /> inside de quote tags. Then it doesn;t recognize it as the same pattern...Jay– Jay2010-07-31 12:43:51 +00:00Commented Jul 31, 2010 at 12:43
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2 Answers
$string = preg_replace('/\[QUOTE=[^\]]*\].*\[\/QUOTE\]/', '', $string);
3 Comments
Jay
seems to work unless there's a <br /> inside de quote tags. Then it doesn;t recognize it as the same pattern
Jhong
It should work with <br />, but it will not match if newlines (\n) are present. add the 's' modifier to the end (after the final '/') to let it match over newlines. However, you might have to also make the ".*" ungreedy by adding a '?' after it.
Jay
not sure (yet) what an s modifier is, but it worked :) thnx again
Jhongs answer is perfect, it will leave you with the content from the both *'s.
However, if you need the parts separately you can make a small adjustment and add capturing groups like so:
if (preg_match('%\[QUOTE=([^\]]*)\](.*)\[/QUOTE\]%', $subject, $matches))
{
...
}
The *'s will be at $matches[1] and $matches[2].
