PHP Json to HTML with an array on json

Question

I have the folowing format of json:

[
    {
        "title": "title will be here",
        "teaser": "teaser will be here...",
        "date": ["2015-11-19T00:00:00"]
   }
]

and the php to read the json:

$json = file_get_contents( "news.json" );
$data = json_decode( $json );
json_decode( json_encode( $data ), true );

foreach ( $data as $object ):
    echo $object->{'title'};
    echo $object->{'teaser'};
    echo $object->{'date'};
endforeach;

the code returns title and teaser but not the date, what should i do to return the date correctly?

The date value is an array; you should see a warning cannot convert Array to string. — Kenney
– Kenney, Commented Nov 20, 2015 at 14:50
why decode/encode/decode again? Why not just a single $data = json_decode($json, true)? and 'date' is an array. you can't echo out an array. $object->date[0], maybe. — Marc B
– Marc B, Commented Nov 20, 2015 at 14:53

Victor Radu · Accepted Answer · 2015-11-20 14:53:52Z

1

your date is in an array so $object->date will return an array. you may only what the first key of the array

date: <?= reset($object->date); ?>

or output all

date: <?php foreach($object->date as $date){echo $date} ?>

edited Nov 20, 2015 at 14:53

answered Nov 20, 2015 at 14:51

Victor Radu

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Comments

Steve · Accepted Answer · 2015-11-20 14:55:30Z

The date property is an array. If it only contains 1 valuu, or you only ever want the 1st value, simply access the 1st element:

$json=file_get_contents("news.json");
$data =  json_decode($json);
foreach($data as $object):
    echo $object->title;
    echo $object->teaser;
    echo $object->date[0];
endforeach;

If you may want to access multiple date values, iterate the array:

foreach($data as $object){
    echo $object->title;
    echo $object->teaser;
    foreach($object->date as $date){
        echo $date;
    }
}

Note i also removed the erroneous json_decode(json_encode($data), true); line and simplified your property access code - all the names are valid property names so no need for the {'...'} syntax

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