Is there a way to achieve conditional ng-pattern in angularjs
ng-pattern="(myForm.exipration.$dirty ? ('/^\d{2}[/]\d{4}$/') : '')"
i tried like above, but does not help.
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2 Answers
Markup
<input ... ng-pattern="handlePatternPassword">
Controller
$scope.handlePatternPassword = (function() {
var regex = /^[A-Za-z0-9!@#$%^&*()_]{4,20}$/;
return {
test: function(value) {
if ($scope.user.isLogged) {
return (value.length > 0) ? regex.test(value) : true;
} else {
return regex.test(value);
}
}
};
})();
3 Comments
Hacker
@ Jonatas Walker - worked perfectly. How does it work?
Jonatas Walker
Inside
test function make your conditionals. Return a boolean for your validation.
jitendra varshney
i dont wanna make function i wanna do this in html but it is not working can you provide answer for using this in html
The following worked for me (AngularJS v1.5.11):
ng-pattern="condition ? '[A-Za-z0-9_-]{1,60}' : ''"
2 Comments
darudude
Do you have a JSFiddle for this? I can't get it to work with this version of AngularJS. here is an example to set a pattern for multiple of 25 jsfiddle.net/9bua4k2d/1
Flash
this doesnt seem to work with the latest version on Angular 7/8
patterm="condition ? '[A-Za-z0-9_-]{1,60}' : '' Do you know of any good solutions