Modifying increment value in for loop

Question

I was playing around with Python 2.7 and wanted to know if there was a clean way to code a Python equivalent of this Java loop (where you can modify the increment value in the loop):

for (int i = 1; i <= 64; i *= 2) {
    # i = 1, 2, 4, 8, 16, 32, 64
}

It seems like in Python you can use range(), but you can only get every nth element (e.g. for i in range(1, 65, 2) will get you every odd element).

Not exactly a duplicate, but you may find dicussion on this question helpful. — BrenBarn
– BrenBarn, Commented Nov 21, 2015 at 8:13

Bhargav Rao · Accepted Answer · 2015-11-21 08:06:19Z

2

Java for loops are different from Python's. You an use a while loop for the same effect.

i = 1
while (i<=64):
    print(i)
    i*=2

Else you can implement your own range function using a custom generator

>>> def my_own_range(n):
...     i = 1
...     while(i<=n):
...         yield(i)
...         i*=2
... 
>>> for i in my_own_range(64):
...     print(i)
... 
1
2
4
8
16
32
64

answered Nov 21, 2015 at 8:06

Bhargav Rao

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