Extract just file path from string

Question

I have a file that contains strings in this format:

MD5 (TestImages/IMG_0627.JPG) = 6ed611b3e777c5f7b729fa2f2412d656

I am trying to figure out a way to extract the file path, so that I would get a string like this:

TestImages/IMG_0627.JPG

For a different part of my script, I am using this code to remove everything before and after the brackets, and I could of course do something similar, however I'm sure there is a better way?

shortFile=${line#*MD5 }
shortFile=${shortFile%%)*}

Anyone have any suggestions?

How about using sed?

jia103
– jia103

2015-11-24 00:27:35 +00:00
Commented Nov 24, 2015 at 0:27 — jia103
– jia103, Commented Nov 24, 2015 at 0:27

miken32 · Accepted Answer · 2015-11-24 00:27:55Z

2

You could use sed but that has the overhead of starting a new process.

echo $line | sed -r 's/MD5 \((.*)\).*/\1/'

answered Nov 24, 2015 at 0:27

miken32

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SergA Over a year ago

Running sed once: sed -r 's/MD5 \((.*)\).*/\1/' <PATH/TO/FILE>

Etan Reisner · Accepted Answer · 2015-11-24 00:45:57Z

2

Just to throw a non-sed answer onto the pile. (Also slightly cheaper since it avoids the pipeline and sub-shell.)

awk -F '[()]' '{print $2}' <<<"$line"

That said the substring expansion option is a reasonable one if it does what you need. (Though it looks like you missed the ( in the first expansion.)

answered Nov 24, 2015 at 0:45

Etan Reisner

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Maddy · Accepted Answer · 2015-11-24 00:33:34Z

1

Another way with cut can be :

echo $line|cut -d "(" -f2|cut -d ")" -f1

answered Nov 24, 2015 at 0:33

Maddy

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jia103 · Accepted Answer · 2015-12-05 06:08:47Z

1

sed -e 's/^.*(\([^)]*\)).*$/\1/' < infile.txt

edited Dec 5, 2015 at 6:08

answered Nov 24, 2015 at 0:31

jia103

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1 Comment

jia103 Over a year ago

I didn't at the time; I did now and updated to correct it.

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