row=['alex','liza','hello **world**','blah']
i do i get everything in row[2] that is between the ** characters?
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like msw said, dont use a chainsaw, regex is a chainsawAlex Gordon– Alex Gordon2010-08-02 19:39:23 +00:00Commented Aug 2, 2010 at 19:39
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4 Answers
You could do it by hand and search for the * , but regex work too.
print re.search(r'\*\*(.*)\*\*', 'hello **world**').group(1) # prints 'world'
You need to know exactly what you're looking for with regex, so think about what **asd**dfe** and similar edge cases should return.
Comments
import re
print re.findall(r"\*\*(.*)\*\*", row[2])
will give you a list of every match in row[2] which is between **. Fine tune the regex as necessary
Comments
Let's say that you don't know which element has the stars, you could use this:
row=['alex','liza','hello **world**','blah']
for staritem in (item for item in row if '**' in item):
print(staritem)
_,_, staritem = staritem.partition('**')
staritem,_,_ = staritem.partition('**')
print(staritem)
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row[2].strip('*')
Don't use a chainsaw when a knife will do.
2 Comments
Alex Gordon
>>> row[2].strip('*') 'hello **world'
Yuval Adam
huh? how do you figure out which part is the one between the
**?