How to stop a python threading script using a GUI

Question

I am using a GUI with a checkbox made with QT and python, when the checkbox is checked i want to display 'stackoverflow' every 5 seconds, when it is unchecked i want it to do nothing. I have tried to call the following function when it is checked:

def work (): 
    threading.Timer(5, work).start ()
    print "stackoverflow"

def checkbox(self, state):
    if state == QtCore.Qt.Checked:
        print 'checked'
        work()
    else: print 'unchecked'

But it keeps on printing 'stackoverflow'. How can i stop this?

You are just launching one thread each time you check the checkbox, in fact you are recursively calling work in each thread, this is pretty bad, i dont know how is not even crashing :/ — Netwave
– Netwave, Commented Nov 26, 2015 at 11:10

FunkySayu · Accepted Answer · 2015-11-26 11:19:07Z

1

Here is a solution.

from threading import Thread
import time

class WorkerThread:

    def __init__(self, timer=5):
        self.timer = timer
        self._alive = False

    def work(self):
        while self._alive:
            time.sleep(self.timer)
            print("Stack Overflow")

    def start(self):
        self._thread = Thread(target=self.work)
        self._alive = True
        self._thread.start()

    def stop(self):
        self._alive = False

worker_thread = WorkerThread()

def checkbox(self, state):
    if state == QtCore.Qt.Checked:
        worker_thread.start()
    else:
        worker_thread.stop()

answered Nov 26, 2015 at 11:19

FunkySayu

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Comments

furas · Accepted Answer · 2015-11-26 11:20:52Z

0

You can use variable to control thread

running = False

def work (): 
    print "stackoverflow"
    if running:
        threading.Timer(5, work).start ()

def checkbox(self, state):
    global running

    if state == QtCore.Qt.Checked:
        print 'checked'
        running = True
        work()
    else: 
        print 'unchecked'
        running = False

answered Nov 26, 2015 at 11:20

furas

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