return regex result from cmd output to variable

Question

I'm looking forward to get a string from an cmd output (ID of tmutil destinationinfo).

I have tested this regex with https://regex101.com/r/aI3yH2/1:

/^.*?Name.+?backup02\nKind.+?\nID?\s+:\s([A-Z0-9\-]+)/s

Looks like it's working, I'm searching for backup01, backup02, ...

But how can I grab the ID to a variable within a shell script?

Output is like this:

====================================================
Name          : backup02
Kind          : Local
Mount Point   : /Volumes/ext_backup01_02
ID            : BC51C9FA-DE8A-4BA3-B23E-AEC10E9E9F69
> ==================================================
Name          : backup01
Kind          : Network
URL           : afp://[email protected]/backup01
Mount Point   : /Volumes/backup01
ID            : 009B3736-61C5-4996-B9BC-A5230BED7961
====================================================
Name          : backup03
Kind          : Network
URL           : afp://[email protected]/backup03
Mount Point   : /Volumes/backup01
ID            : 1E9A3734-33D6-1316-C9B4-B143DA35D9F2

I really don't know how to handle this. Sample code 100% not working:

#!/bin/bash
ID=$(tmutil destinationinfo | sed -E '/^.*?Name.+?backup02\nKind.+?\nID?\s+:\s([A-Z0-9\-]+)/s')
echo $ID

Thanks!

rici · Accepted Answer · 2015-11-28 03:03:12Z

1

sed (and grep, which would be the other popular regex matcher) are line-oriented; they process one line at a time. So multiline patterns won't work.

You can get sed to accumulate lines, but it's not very pretty. If you did that, you would find that the regex dialect recognized by sed is quite different from the one you are using in the online tool. In particular, sed doesn't implement non-greedy match.

You can probably do better with awk:

awk -F '[[:space:]]*:[[:space:]]*' \
    '$1 == "Name" && $2 == "backup02" { this_one = 1 }
     this_one && $1 == "ID" { print $2; exit }'

answered Nov 28, 2015 at 3:03

rici

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