compiler error: array required, but String found

Question

Getting a error: array required, but String found. I checked and rechecked, yet couldn't find anything wrong with my code. What's going wrong? I have been introduced to java a year ago, but only when i started working on a project to develop a library management system do I realise the serious deficiencies in my knowledge.

import java.util.Scanner;

public class library{
book[] bk = new book[5];

public static void main(String[] args){
    Scanner input = new Scanner(System.in);
    library mainObj = new library();

    mainObj.addBooks();
}

public void addBooks(){
    Scanner input = new Scanner(System.in);

    System.out.print("Book Name: ");
    String bk = input.nextLine();

    System.out.print("Author Name: ");
    String aun = input.nextLine();

    System.out.print("Id: ");
    String i = input.nextLine();

    bk[book.getTotalBookCount()] = new book(bk, aun, i);
}

}

class book{
String name;
String authorName;
String id;
static int totalBookCount = 0;

book(String bkn, String aun, String i){
    name = bkn;
    authorName = aun;
    id = i;
    totalBookCount++;

    System.out.println("Book Added!! ");
}

}

Please provide minimal reproducible example (pay attention to "minimal"), at very least point to location of the error. — Alexei Levenkov
– Alexei Levenkov, Commented Nov 28, 2015 at 4:05
library.java:39: error: array required, but String found bk[book.getTotalBookCount()] = new book(bk, aun, i); ^ 1 error — ooodddbbb
– ooodddbbb, Commented Nov 28, 2015 at 4:08
Thanks for the edit - strive for sample without vertical scroll and try to avoid unnecessary inputs that may in some cases impact result (i.e. you could replace all input statements with constants like String bk="book name";). Note that using good long names let you avoid such problem. — Alexei Levenkov
– Alexei Levenkov, Commented Nov 28, 2015 at 4:16

Sarvadi · Accepted Answer · 2015-11-28 04:08:33Z

2

String bk = input.nextLine();

You're shadowing book[] bk with that variable. Either change the name of one of them, or use this instead.

this.bk[book.getTotalBookCount()] = new book(bk, aun, i);

answered Nov 28, 2015 at 4:08

Sarvadi

5603 silver badges15 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Furqan Aziz · Accepted Answer · 2015-11-28 04:10:58Z

1

You are using bk variable twice. Once at top while declaring array book[] bk = new book[5]; and once in addBooks function String bk = input.nextLine(); at third line.

answered Nov 28, 2015 at 4:10

Furqan Aziz

1,1149 silver badges18 bronze badges

Comments

Ashish Ani · Accepted Answer · 2015-11-28 06:18:49Z

1

You have used bk twice for two different types i.e. one for book array and another for string. And in these type of collisions, local type gets priority so,

 bk[.....] = ......;
 ^^^^^   
Here, `bk` will be considered as string, but we are using `[]` brackets with it, hence the error: array required, string found.

answered Nov 28, 2015 at 6:18

Ashish Ani

3321 silver badge7 bronze badges

Collectives™ on Stack Overflow

compiler error: array required, but String found

3 Answers 3

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related