Error using arrays in shell script

Question

I was testing a shell script in which arrays were used. This is an example taken from tutorialspoint

#!/bin/sh

NAME[0]="Zara"
NAME[1]="Qadir"
NAME[2]="Mahnaz"
NAME[3]="Ayan"
NAME[4]="Daisy"
echo "First Index: ${NAME[0]}"
echo "Second Index: ${NAME[1]}"

But I am getting this error
test.sh: 3: test.sh: NAME[0]=Zara: not found
test.sh: 4: test.sh: NAME[1]=Qadir: not found
test.sh: 5: test.sh: NAME[2]=Mahnaz: not found
test.sh: 6: test.sh: NAME[3]=Ayan: not found
test.sh: 7: test.sh: NAME[4]=Daisy: not found
test.sh: 8: test.sh: Bad substitution

The link to the exact page is here

Karoly Horvath · Accepted Answer · 2015-11-29 18:27:41Z

4

The shebang is wrong, this only works in specific shells, e.g. bash.

answered Nov 29, 2015 at 18:27

Karoly Horvath

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1 Comment

Vrushab Maitri Over a year ago

It's working when i execute the code as > bash test.sh

pro_cheats · Accepted Answer · 2015-11-29 18:39:52Z

1

Simple. You just need to run as -

bash script_name.sh

answered Nov 29, 2015 at 18:39

pro_cheats

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