How to construct a javascript regex to extract all string after a special string?

Question

I have this string :

"AED 149: "Instant Redemption A 10AED""

How can I have a regex that will get me this text ?

"Instant Redemption A 10AED"

currently I have this

var regEx = new RegExp(currency + ' ' + '[\\d,.]+: (.*)', "ig");

in which currency value is AED now.

but this return for me "AED 149: "Instant Redemption A 10AED"" as a match

Can I modify my regex to have this result only : "Instant Redemption A 10AED" ?

how my regEx variable will be then ? "Instant Redemption A 10AED" is not a fixed text it could be any string, but this one is fixed AED 149: in which AED = currency — user123456
– user123456, Commented Dec 1, 2015 at 7:58

anubhava · Accepted Answer · 2015-12-01 08:05:44Z

2

Transferring my comment into answer for better understanding.

Your regex is fine but global flag is not needed. You just need to use captured group #1 like this:

var currency = 'AED'    
var regEx = new RegExp(currency + ' ' + '[\\d,.]+: (.*)', "i");    
var s = 'AED 149: "Instant Redemption A 10AED"'

var m = s.match(regEx);

console.log(m[1]);
//=> "Instant Redemption A 10AED"

answered Dec 1, 2015 at 8:05

anubhava

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Zakaria Acharki · Accepted Answer · 2015-12-01 07:59:48Z

0

If you have always the same format you can get it without regex, just using split :

var my_string = 'AED 149: "Instant Redemption A 10AED"';
my_string.split(':')[1]; //Will return "Instant Redemption A 10AED"

Hope this helps.

answered Dec 1, 2015 at 7:59

Zakaria Acharki

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Mayur Koshti · Accepted Answer · 2015-12-01 08:06:04Z

0

var str = "AED 149: "Instant Redemption A 10AED"";
str.replace(/[^\:]+\:[^\"]+\"([^\"]+)\"/, "$1");

answered Dec 1, 2015 at 8:06

Mayur Koshti

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