HTTP POST using JSON in Spring Rest

Question

I would like to make a simple HTTP POST using Spring RestTemplate. the Wesb service accept JSON in parameter for example: {"name":"mame","email":"[email protected]"}

   public static void main(String[] args) {

    final String uri = "url";
    RestTemplate restTemplate = new RestTemplate();
    // Add the Jackson message converter
    restTemplate.getMessageConverters().add(new MappingJackson2HttpMessageConverter());
    // create request body
    String input = "{   \"name\": \"name\",   \"email\": \"[email protected]\" }";
    JsonObject request = new JsonObject();
    request.addProperty("model", input);

    // set headers
    HttpHeaders headers = new HttpHeaders();
    headers.setContentType(MediaType.APPLICATION_JSON);
    headers.set("Authorization", "Basic " + "xxxxxxxxxxxx");
    HttpEntity<String> entity = new HttpEntity<String>(request.toString(), headers);

    // send request and parse result
    ResponseEntity<String> response = restTemplate
            .exchange(uri, HttpMethod.POST, entity, String.class);

    System.out.println(response);
}

When I test this code I got this error:

 Exception in thread "main" org.springframework.web.client.HttpClientErrorException: 400 Bad Request

when I call webservice with Curl I have correct result:

 curl -X POST -H "Authorization: Basic xxxxxxxxxx" --header "Content-Type: application/json" --header "Accept: application/json" -d "{   \"name\": \"name\",   \"email\": \"[email protected]\" } " "url"

add the webservice code you are trying to reach and screenshot of postman or curl expression which is executed correctly... — Nikolay Rusev
– Nikolay Rusev, Commented Dec 2, 2015 at 15:23
I'haven't access to webservice. by using curl I can call ws using this command: curl -X POST -H "Authorization: Basic xxxxxxxxxx" --header "Content-Type: application/json" --header "Accept: application/json" -d "{ \"name\": \"name\", \"email\": \"[email protected]\" } " "url" — youssef Liouene
– youssef Liouene, Commented Dec 2, 2015 at 15:34

Nikolay Rusev · Accepted Answer · 2015-12-02 15:46:15Z

16

try to remove model from the code, as i can see in your curl request you didn't use model attribute and everything works. try this:

 public static void main(String[] args) {

    final String uri = "url";
    RestTemplate restTemplate = new RestTemplate();
    // Add the Jackson message converter
    restTemplate.getMessageConverters().add(new MappingJackson2HttpMessageConverter());
    // create request body
    String input = "{\"name\":\"name\",\"email\":\"[email protected]\"}";


    // set headers
    HttpHeaders headers = new HttpHeaders();
    headers.setContentType(MediaType.APPLICATION_JSON);
    headers.set("Authorization", "Basic " + "xxxxxxxxxxxx");
    HttpEntity<String> entity = new HttpEntity<String>(input, headers);

    // send request and parse result
    ResponseEntity<String> response = restTemplate
            .exchange(uri, HttpMethod.POST, entity, String.class);

    System.out.println(response);
}

answered Dec 2, 2015 at 15:46

Nikolay Rusev

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1 Comment

fall Over a year ago

Can the message converter convert a Java object into json string? Let's say input is an ojbect of type User. User = new User("name", "[email protected]");

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