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I have an ArrayList which holds employee record details from data inputted into JTextFields. I have displayed this with a showMessageDialog box to confirm that they are being added to the list correctly.

The employees are created and added to the list correctly but how do I cycle through the ArrayList one record at a time and have the information displayed in the JTextFields?

Edited as below:

I don't think I have asked the question properly. I have a button that enables me to show the contents of the first element of my array list to the GUI. See below:

nField.setText(nameList.get(0).getName()); bField.setText(nameList.get(0).getBirth()); jField.setText(nameList.get(0).getID());

What I need is something to show the next element.

I have a list iterator that I am trying to use but I simply can’t get it to work.

I have tried this but it results in the last element being shown:

for (int i = 0; i < nameList.size(); i++) {

nameList.get(i);

nField.setText(nameList.get(i).getName()); bField.setText(nameList.get(i).getBirth()); jfield.setText(nameList.get(i).getID()); }

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2 Answers 2

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There are different options, but the short of it is, you'll have to tie your employee record to the JTextField somehow. One way to do this is by creating a simple object to hold the relation:

public class EmployeeRecordToJTextfield {
  private EmployeeRecord employeeRecord;
  private JTextField jTextField;

  public EmployeeRecordToJTextfield(EmployeeRecord employeeRecord, JTextField jTextField) {
    this.employeeRecord = employeeRecord;
    this.jTextField = jTextField;
  }

  public EmployeeRecord getEmployeeRecord() {
    return employeeRecord;
  }

  public JTextField getJTextField() {
    return jTextField;
  }
}

Instead of the EmployeeRecord, you stick instances of this class in the list:

List<EmployeeRecordToJTextfield> list = new ArrayList<>();
list.add(new EmployeeRecordToJTextfield(employeeRecord, jTextField));

When you iterate over this list, you can transfer the data you choose:

for (EmployeeRecordToJTextfield e : list) {
  JTextField textField = e.getJTextField();
  EmployeeRecord record = e.getEmployeeRecord();
  textField.setText(record.getName());
}

Another option, maybe simpler, is by converting your list to a map and map EmployeeRecords to their JTextField.

Update based on the Question update

I hope I now understand what you're asking, but if so, I'd just do this:

Store the index of the 'current' shown item in a variable or hidden GUI field.

private int currentIndex = 0; // Start with the first item.

When you want to show the next item (perhaps through a Next or Previous button), get the next value. Compensate for list length:

int nextIndex = currentIndex+1;
if (nextIndex >= nameList.size()) nextIndex = 0;
if (nextIndex < 0) nextIndex = nameList.size()-1;

Now you can use nextIndex to fetch the correct entry from your list:

nField.setText(nameList.get(nextIndex).getName());
bField.setText(nameList.get(nextIndex).getBirth()); 
jfield.setText(nameList.get(nextIndex).getID());

And don't forget to update the currentIndex:

this.currentIndex = nextIndex;
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5 Comments

I very much appreciate your reply but I think I over complicated the question. I have edited my question and included source code.
@JavaNewbie I updated the answer, is this what you're looking for?
Perfect, thank you Ricardo. This has really helped. It even goes back to the first record after the final record. I have used the same code for the previous button but used currentIndex-1. This works until you get to the first record. It then breaks down when you try to go to the previous record. What am I missing?
@JavaNewbie You'd have to add a line to cover for when you're on the first element: if (nextIndex < 0) nextIndex = nameList.size()-1;
Can't thank you enough. Been struggling with this for a while and can finally move on to other aspects. You are a credit to the site.
0

Use for loop:

for(JTextField a : your_list){
    do_something();
}
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