Python call URL with key=value pairs

Question

Since I do my first steps in Python, I try to figure out, how can I do a simple URL call in Python with key=value pairs like:

http://somehost/somecontroller/action?key1=value1&key2=value2

I tried with some things like:

key1 = 'value'
key2 = 10
requests.get("http://somehost/somecontroller/action?key1=" + value + "&key2=" + str(10))

or

data={'key1': 'value', 'key2': str(10)}
requests.get("http://somehost/somecontroller/action", params=data)

(from here)

But this don't work. I also tried it by calling curl with subprocess.Popen() on different ways, but uhm...

I don't want to check the request, the URL call will be enough.

Thanks for the link, but I already tried this solution. It don't work for me. — Rico
– Rico, Commented Dec 4, 2015 at 0:36
I think you have typo data = { 'key1': 'value', 'key2': str(10) }. What error are you getting? How do you know it's not working? — willoller
– willoller, Commented Dec 4, 2015 at 0:41
Try data={'key1': 'value', 'key2': '10'}; requests.get("http://127.0.0.1:5000/", params=data), the url will be http://127.0.0.1:5000/?key1=value&key2=10. — Remi Guan
– Remi Guan, Commented Dec 4, 2015 at 0:47
There is no error, the url is simply not build for my needs. when I print the request.url it shows only "somehost/somecontroller" in most of the cases. Missing the action and of course, the kay value part. — Rico
– Rico, Commented Dec 4, 2015 at 1:02

memoselyk · Accepted Answer · 2015-12-04 04:52:28Z

0

Using the requests library you can use PreparedRequest.prepare_url to encode the parameters to an url, like:

import requests
p = requests.models.PreparedRequest()

data={'key1': 'value', 'key2': str(10)}
p.prepare_url(url='http://somehost.com/somecontroller/action', params=data)

print p.url

In the last print, you should get:

http://somehost.com/somecontroller/action?key2=10&key1=value

answered Dec 4, 2015 at 4:52

memoselyk

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