Argument parser with mixed type of args input in Python's argparse module

Question

I have the following script:

import argparse
parser = argparse.ArgumentParser()
parser.add_argument("-s",metavar="",help="some help",type=int,default=0.5)
print parser.parse_args()

The 3rd line, I'd like to have the type of int and string. So the user can use one of these values [0, 0.1, 0.2, 0.3, 0.5, 'best'].

How can I do that?

why not just take in a string and try casts

Ayush
– Ayush

2015-12-04 03:22:48 +00:00
Commented Dec 4, 2015 at 3:22 — Ayush
– Ayush, Commented Dec 4, 2015 at 3:22

eph · Accepted Answer · 2015-12-04 03:43:19Z

8

The type argument can be considered as a convert function instead of data type.

So you can add a converter like this:

def int_or_str(value):
    try:
        return int(value)
    except:
        return value

and pass as type.

edited Dec 4, 2015 at 3:43

answered Dec 4, 2015 at 3:24

eph

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6 Comments

neversaint Over a year ago

what do you mean pass as 'type'. If I do it your way, what value should I give to type?

eph Over a year ago

@neversaint type=int_ot_str

eph Over a year ago

@neversaint I just put my code on top of your code and replace type=int as type=int_ot_str, it works.

neversaint Over a year ago

running example in ipython, please. I got NameError: global name 'in_ot_str' is not defined.

memoselyk Over a year ago

@eph The question actually includes 0.3 which is a float not an int.

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