I am trying to make a vector out of two different ones as shown in the piece of code below. However, I get a list out of range exception on the 5th line the first time the code goes in the for loop.
What am I doing wrong?
def get_two_dimensional_vector(speeds, directions):
vector = []
for i in range(10):
if (i % 2 == 0):
vector[i/2][0] = speeds[i/2]
else :
vector[i/2 - 1/2][1] = directions[i/2 - 1/2]
You can't use a Python list this way. It's not like a C array with a
predefined length. If you want to add a new element, you have to use the
append method or something.
Aside from that, you're also using a second index, implying that the
elements of vector are themselves lists or dicts or something, before
they've even been assigned.
It looks like you want to convert speeds and directions to a
two-dimensional list. So, first, here's how to do that with a loop. Note
that I've removed the fixed-size assumption you were using, though the
code still assumes that speeds and directions are the same size.
def get_two_dimensional_vector(speeds, directions):
vector = []
for i in range(len(speeds)):
vector.append([speeds[i], directions[i]])
return vector
speeds = [1, 2, 3]
directions = [4, 5, 6]
v = get_two_dimensional_vector(speeds, directions)
print(v)
Now, the Pythonic way to do it.
print(zip(speeds, directions))
enumeratein the loopvectoris only a list. That's why he gets the out of index error. I am not sure if the duplicated question has something to do with this one.