Running a makefile using shell script

Question

I have a directory structure as follows:

.
├── one
│   ├── one_one
│   │   └── one_one_one
│   │       ├── Makefile
│   │       └── one_one_oneTest.cpp
│   └── one_two
│       ├── Makefile
│       └── one_twoTest.cpp
├── three
│   ├── Makefile
│   └── threeTest.cpp
└── two
    └── two_one
        ├── Makefile
        └── two_oneTest.cpp

I want to run the make command where ever I find the Makefile. So, I have written a shell script as follows.

#!/bin/bash
find . -type f -name Makefile -exec make \;

But it gives error saying make: *** No targets specified and no makefile found. Stop.

If I just run find . -type f -name Makefile, I get

./two/two_one/Makefile
./three/Makefile
./one/one_two/Makefile
./one/one_one/one_one_one/Makefile

which is the correct output I expected.

If I run the Makefile using make command, it runs properly, so I think the Makefile is correct. What can be wrong with the shell script?

Just for reference, one of my Makefiles is as follows:

all: TestTwoOne

TestTwoOne: two_oneTest.cpp
    g++ two_oneTest.cpp -o TestTwoOne

Jeff Y · Accepted Answer · 2015-12-06 17:26:47Z

4

Your "current directory" is not being changed to the appropriate subdirectories for running the make. Do this instead:

find . -type f -name Makefile -execdir make \;

answered Dec 6, 2015 at 17:26

Jeff Y

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