Tuple to List Python

Question

I have a tuple like this

rows = ((1L, 100000L, 'logo', '0'), (2L, 100000L, 'menu', '0'))

And I want to turn it into this

[[1L, 100000L, 'logo', '0'], [2L, 100000L, 'menu', '0']]

Here is what I am trying

for idx, val in enumerate(rows):
    print list(rows[idx])

And

for idx, val in enumerate(rows):
     print list(val)

but neither prints out anything and there is no error. It just doesn't do anything. I know the variable rows has this value because I print it out before I go thought the loop.

How can I turn the tuple in to an array of arrays?

Mike Müller · Accepted Answer · 2015-12-07 06:20:49Z

3

Try this:

list(map(list, rows))

The built-in list converts anything into a list that is iterable, i.e. you can write a forloop for it. The map applies the function list to the tuples inside the tuple.

An alternative would be a nested list comprehension:

[[x for x in t] for t in rows]

List comprehensions are essentially loops in one line. They can only contain expressions. "Normal" loops can contain statements and are typically better suited for multi-line solutions.

edited Dec 7, 2015 at 6:20

answered Dec 6, 2015 at 22:42

Mike Müller

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Zizouz212 · Accepted Answer · 2015-12-06 22:42:01Z

0

What about:

new_rows = []
for i in rows:
    rows.append(list(i))

answered Dec 6, 2015 at 22:42

Zizouz212

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Gord Thompson · Accepted Answer · 2015-12-06 22:47:27Z

0

This seems to work for me:

>>> rows = ((1L, 100000L, 'logo', '0'), (2L, 100000L, 'menu', '0'))
>>> [list(x) for x in rows]
[[1L, 100000L, 'logo', '0'], [2L, 100000L, 'menu', '0']]

answered Dec 6, 2015 at 22:47

Gord Thompson

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