Python: Manipulate an array

Question

I have an array that looks just like this one:

 array(['00:00;1;5950;6\r', '00:10;1;2115;6\r', '00:10;2;4130;6\r',
   '00:10;3;5675;6\r', '00:20;1;1785;6\r'], 
  dtype='|S15')

For my evaluation I need only the value after the second semicolon at each array entry. Here in this example, I need the values:

5950, 2115, 4130, 5675, 1785.

Is it possible to manipulate the array in way to get the entries I want? And how can that be solved? I know how to remove the symbols, so in the end I get the array:

['0000159506\r', '0010121156\r', '0010241306\r', '0010356756\r', '0020117856\r']

But I don't know if this is the right way to handle these problem. Do anyone know what to do? Thank you very much!

farhawa · Accepted Answer · 2015-12-07 20:48:51Z

2

Try this:

A = array(['00:00;1;5950;6\r', '00:10;1;2115;6\r', '00:10;2;4130;6\r',
   '00:10;3;5675;6\r', '00:20;1;1785;6\r'], 
  dtype='|S15')
list_ = [str(x.split(";")[2]) for x in A]

edited Dec 7, 2015 at 20:48

answered Dec 7, 2015 at 14:54

farhawa

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1 Comment

kmonsoor Over a year ago

Don't get the float part. Target output is str, then why cast to float?

NendoTaka · Accepted Answer · 2015-12-07 16:38:32Z

1

The best way to get these values is to use the python split function.

You can choose the delimiter. So in this case the delimiter can be a ;.

result = line.split(';')

and then just find the third value of the resulting list.

num = result[2]

edited Dec 7, 2015 at 16:38

answered Dec 7, 2015 at 14:54

NendoTaka

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1 Comment

elly Over a year ago

Yes thank you! That was exactly what I was searching for.

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