Jenssegers Laravel-Mongodb return null if get by parameter

Question

I'm new to Laravel-Mongodb, trying to get result by parameter but it's not working

Model:

use Jenssegers\Mongodb\Model as Eloquent;

class Customer extends Eloquent {
    protected $connection = 'mongodb';
    protected $collection = 'Customer';
}

Controller:

class AdminController extends Controller
{
    public function index() {
        return Customer::all();
    }

    public function show($id) {
        return Customer::find($id);
    }
}

It's alright for index() but it will return empty for show($id), it will work if using:

return Customer::find(1);

I'm not sure why it's not working with parameter, am I missing something?

Harsh Virani · Accepted Answer · 2018-07-07 19:56:44Z

1

You need to add one protected variable in your model like below

protected $primaryKey = “customerId”

You can add your own primary key to this variable but if you won’t add this line in model, model will by default take _id as your primary key and _id is autogenerated mongodb’s unique id.

Thats the reason why you are not able to get record by id.

answered Jul 7, 2018 at 19:56

Harsh Virani

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Comments

tommy · Accepted Answer · 2015-12-07 20:31:54Z

0

1 is not a valid ObjectId. Try to find a valid ID with a tool like Robomongo or just list your customers with your index method to find out what the IDs are.

The query should look more like this:

return Customer::find("507f1f77bcf86cd799439011");

You can read more about MongoDBs ObjectId here:

https://docs.mongodb.org/manual/reference/object-id/

answered Dec 7, 2015 at 20:31

tommy

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1 Comment

Siu San Over a year ago

ic...it's strange that if I doing Customer::where('_id', $id)->get(); is not working but Customer::where('_id', 1)->get(); is work, don't know why, is it the same problem?

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