JQuery Ajax returning bool(false)

Question

I've been looking at other questions related to my problem however none seem to correspond to my exact circumstances. I'm attempting to create a javascript variable which I will POST with Ajax to a PHP variable further down in my code. After hopefully setting the variable correctly I attempt to POST and var_dump the result however it is not the "0" I had hoped for but rather a frustrating bool(false). I've read that this may be a problem with the url (as I POST from the same file) or perhaps some other issue to do with the transfer of data to the Ajax request though I have as yet been unable to work out the issue. Testing for the data in the console also shows nothing so I've been forced to ask here. Thank you for any help or guidance.

Javascript

jQuery(document).ready(function(){var offset = parseInt("0");
        $.ajax({url: 'index.php', type: 'POST', data: offset, success:function(data){return data;}});
    });

PHP

<?php var_dump(isset($_POST['offset']));

yep! everything returns the same bool(false) response I'm afraid — masteryupa
– masteryupa, Commented Dec 10, 2015 at 8:29
Convert your offset to string '0' then change it on server side. — aldrin27
– aldrin27, Commented Dec 10, 2015 at 8:30

roullie · Accepted Answer · 2015-12-10 08:29:40Z

3

add an index called offfest

$.ajax({
    url: 'index.php', 
    type: 'POST', 
    data: {offset:offset}, 
    success:function(data){
        return data;
    }
});

answered Dec 10, 2015 at 8:29

roullie

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2 Comments

masteryupa Over a year ago

This was how I had set up the request earlier (changed it just to see if trying anything different would work). Giving a shot now hasn't changed anything though so I think there is something else going on.

roullie Over a year ago

hmm. are there any console errors? and can you see the request being sent to the server?

jiboulex · Accepted Answer · 2015-12-10 08:29:47Z

3

you can try with :

jQuery(document).ready(function(){
    $.ajax({url: 'index.php', type: 'POST', data: {offset: parseInt("0")}, success:function(data){return data;}});
});

answered Dec 10, 2015 at 8:29

jiboulex

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1 Comment

masteryupa Over a year ago

I feel like your answer should definitely work but it just returns the same answer. There's got to be something else going on in the background that I'm not aware of. Thank you though, this was very useful

Vahid Msm · Accepted Answer · 2015-12-10 08:29:27Z

2

I'm not totally familiar with PHP but in your javascript code, data should be dictionary for Ajax post. something like {'offset': 0}

answered Dec 10, 2015 at 8:29

Vahid Msm

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Comments

Cerbrus · Accepted Answer · 2015-12-10 09:02:46Z

1

Your problem is that you're using var_dump in your php.
That literally returns the string: "bool(true)".

Use var_export, instead.

Instead of:

<?php var_dump(isset($_POST['offset'])); ?>

Use:

<?php var_export(isset($_POST['offset'])); ?>

var_export will output the string representation of the value, instead of the type / value combo var_dump returns.

If you just want to return the posted value, do this:

<?php var_export($_POST['offset']); ?>

Or:

<?php echo json_encode($_POST['offset']); ?>

Just keep in mind that you need to pass the data to the post, correctly:

data: { offset: offset }

Instead of:

data: offset

edited Dec 10, 2015 at 9:02

answered Dec 10, 2015 at 8:38

Cerbrus

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12 Comments

masteryupa Over a year ago

Let me tell you I am having a hell of a time testing all of these options. This now returns false

Rene Korss Over a year ago

As OP said: "however it is not the "0" I had hoped for but rather a frustrating bool(false)". @Cerbrus, try my answer.

Cerbrus Over a year ago

ReneKorss: That would mean the OP literally wants returned what he's sending to the php. @masteryupa: What exactly do you want returned from the server?

Cerbrus Over a year ago

Right. Now all you need to do is properly pass the data to the php call, as mentioned in other answers: data: { offset: offset }

Cerbrus Over a year ago

Hm, that's weird. No idea why that error is showing.

|

madalinivascu · Accepted Answer · 2015-12-10 09:08:58Z

1

Js:

var offset = parseInt("0");
$.ajax({url: 'index.php', type: 'POST', data:{offset: offset},success:function(data){alert(data.offset);}});

php:

<?php echo json_encode(array('offset'=>isset($_POST['offset'])));

edited Dec 10, 2015 at 9:08

answered Dec 10, 2015 at 8:38

madalinivascu

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2 Comments

masteryupa Over a year ago

Thanks for your reply. Am now receiving this error

Notice: Use of undefined constant offset - assumed 'offset' in /Applications/XAMPP/xamppfiles/htdocs/parable/index.php on line 149 {"offset":false}

masteryupa Over a year ago

Thank you. Now simply {"offset":false}

ZuoTao.Chou · Accepted Answer · 2015-12-10 08:33:27Z

0

you should give a name to the offset variable so , change your data parameter into a JSON format :

$.ajax({url: 'index.php', type: 'POST', data:{ 'offset': offset},success:function(data){return data;}});

answered Dec 10, 2015 at 8:33

ZuoTao.Chou

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