Php Json Get Value Array Index?

Question

I have this code:

{"DT_RowId":"row_8","siparisler":{"id":"8","tarih":"14-12-2015","uid":"118","mid":"4","satis_fiyati":"5","adet":"7","odeme":"1","olusturan":"ares","sonduzenleyen":""},"urunler":{"urun_adi":"BANNER 100 AH","stok_kodu":"10010"},"musteriler":{"unvan":"3A Otomotiv San. Tic. Ltd. \u015eti."},"kdvsiz":"4.23728813559","kdv":"0.762711864407","top":"35"}

How can get siparisler id with array index?

$result2 = json_decode ($val,true);
return $result2[1][0];

I want to get that with array index because my JSON names are always different.

or how can i get second array name for if control ?

Yes Andrew but my siparisler name always differnt i need get with array index — Cenk YAGMUR
– Cenk YAGMUR, Commented Dec 14, 2015 at 15:42

Fabian Schmengler · Accepted Answer · 2015-12-14 16:11:31Z

2

you could use array_values() to normalize the arrays:

return array_values(array_values(json_decode($val, true))[1])[0];

array_values() returns all the values from the array and indexes the array numerically.

The same split into multiple statements to be more clear:

$result = json_decode($val, true);
$result = array_values($result)[1];
$result = array_values($result)[0];
return $result;

Or for PHP 5.3 and below:

$result = json_decode($val, true);
$result = array_values($result);
$result = array_values($result[1]);
return $result[0];

edited Dec 14, 2015 at 16:11

answered Dec 14, 2015 at 15:54

Fabian Schmengler

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7 Comments

Cenk YAGMUR Over a year ago

This code right ? coz I keep getting error ? Thank you

Fabian Schmengler Over a year ago

are you using an outdated PHP version? Array dereferencing (func()[]) was introduced in 5.4

Fabian Schmengler Over a year ago

5.3 is no longer supported. Please consider updating to at least 5.5

Fabian Schmengler Over a year ago

Nonetheless, I updated the answer with a solution for 5.3

Cenk YAGMUR Over a year ago

Thank you, you are awesome.

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